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Suppose f(1)=3 , f'(1)=2 , g(2)=2 , g'(2)=6 , h(x)=g(2x) , and F(x)=(f(x)/g(2x)) .
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Oh sorry! I need to find h'(1) then F'(1)
h(x) = g(2x) So, h'(x) = 2 g(2x) Therefore, by substitution, h'(1) = 2 g(2) = 2(2) = 4.
for F'(1), take the derivative using the quotient rule, and the same idea as before.
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