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Mathematics 9 Online
OpenStudy (anonymous):

find the value of x

OpenStudy (anonymous):

OpenStudy (anonymous):

@fortune_paul can u help

OpenStudy (anonymous):

can you help

OpenStudy (anonymous):

@zach1751 can you help find the value of x

OpenStudy (anonymous):

im trying to remember how to do this 1 sec

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok you are trying to figure out the cos

OpenStudy (anonymous):

whats the value of x

OpenStudy (anonymous):

i meant what you mean i have to find the value of x

OpenStudy (anonymous):

yes but you have to know the cos to find x take a look at this http://www.coolmath.com/reference/triangles-trigonmetry.html

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i got 94=x

OpenStudy (anonymous):

its not it its not in the answer choice

OpenStudy (anonymous):

am i close to any of them?

OpenStudy (anonymous):

can you list them for me

OpenStudy (anonymous):

A. 32 B. 50 C. 64 D. 80

OpenStudy (anonymous):

ok let me think

OpenStudy (anonymous):

@tkhunny

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

i was wrong all along this isnt trig functions its just a simple ratio

OpenStudy (tkhunny):

Corresponding parts opf similar triangles are proportional. Compare all these: 40:80 25:50 32:x Should be the same ration for each.

OpenStudy (anonymous):

i tried to made that far to difficult

OpenStudy (anonymous):

ok @zach1751 what is it

OpenStudy (anonymous):

its 64

OpenStudy (anonymous):

ok do you have anything else you need help with? sorry i took so long on the last one

OpenStudy (anonymous):

Find the length of the mid-segment

OpenStudy (anonymous):

ok this is the same basic idea

OpenStudy (tkhunny):

@DeeBush96 You have shown no work of your own. This is no good. This last problem is EXACTLY the same as two others. Please show your best efforts. We should not be doing your homework for you.

OpenStudy (anonymous):

ok @DeeBush96 how do you think we should do this?

OpenStudy (anonymous):

compare like terms

OpenStudy (anonymous):

ok yes can you set up the ratios ?

OpenStudy (tkhunny):

Corresponding parts of similar triangles are proportional.

OpenStudy (anonymous):

4x+2=4x +44 + 56 + 56 + 47 + 47

OpenStudy (anonymous):

not exactly i think what you are trying to do is find the perimeter of the larger triangle. can you see that there is a larger and smaller triangle?

OpenStudy (anonymous):

yes

OpenStudy (tkhunny):

Why are you throwing the world into a blender. Just deal with the corresponding parts. 47 : 47+47 56 : 56+56 4x+2 : 4x+44

OpenStudy (anonymous):

do the ratios that he put make sense to you?

OpenStudy (anonymous):

8x + 46 + 94 + 112

OpenStudy (anonymous):

ok thats wrong again ill try to get you on the right course

OpenStudy (anonymous):

can you this give me the answer please

OpenStudy (anonymous):

\[\frac{ 4x+2 }{ 4x+44 }=\frac{ 47 }{ 94 }\]

OpenStudy (anonymous):

now cross multiply

OpenStudy (anonymous):

176 +8

OpenStudy (anonymous):

you should have gotten something like 94(4x+2)=47(4x+44) do you see how i got that?

OpenStudy (anonymous):

ok man i have to go sorry i was not able to explain it all but x=10

OpenStudy (tkhunny):

Please solve this for x \(\dfrac{x}{2} = \dfrac{4}{3}\) Go!

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