Help! Iv'e done these questions a million times but none of them add up. Here it is; 1. x-3y=15 put in slope intecept form 2. Solve with substitution 2x+3y=6 x-3y=15 3. Solve with elimination 2x+3y=6 x-3y=15 Can you PLEASE show me how you do it because evrything ive done doesnt make any sense
1. put in the form y=mx+b 2.solve for one variable in one equation then plug into and get a numerical value in the other equation, then plug that into the first equation to get the value of the other variable. 3. plug in 0 for x or y then solve one equation for the remaining variable then plug into the other
1) solve for y to get the form y=mx+b, where b is the y-intercept and m is the slope. 2) bring the 3y over in the second equation and then that will give you x=3y+15, do you agree? you can then plug that into the first equation and solve for x. Once you have x you can then solve for y. 3) You can add the two equations (as in putting one on top of the other), and then this will cause the 3y to cancel and then adding everything together, you can then solve for x.
Thankyou
You're welcome!
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