Question

How do you put the points (-3,0) and (0,6) into a standard form?

Answer 1

what is slope of the line that these 2 points are on

Answer 2

use the slope formula to figure out the slope. then after that you can use the point-slope formula to get to standard form :D (ax+by=c)

Answer 3

do you know how to find the slope ?

Answer 4

ok, now I need help solving: y-2=1/2x(x+5)

Answer 5

@eohmeo @texaschic101

Answer 6

did you get the first problem ? Now you need help with the other one ?

Answer 7

y - 2 = 1/2(x + 5)
Is this your problem ?

Answer 8

no I didn't figure out the other problem (I forgot to add "the x-intercept is 6 and the y-intercept is 3" and then I changed them into points" in the question. maybe you can also help me with this one? @texaschic101

Answer 9

yes y-2=1/2(x+5) is the one im working on

Answer 10

y - 2 = 1/2(x + 5)
y - 2 = 1/2x + 5/2
y = 1/2x + 5/2 + 2
y = 1/2x + 5/2 + 4/2
y = 1/2x + 9/2

Answer 11

you need me to do the first problem ?

Answer 12

yes please! thanks so much

Answer 13

oh wait for the y=1/2x+9/2, how did you add two to both sides and add 4/2 to 5/2?

Answer 14

first we need to find the slope by using the slope formula :
slope(m) = (y2 - y1) / (x2 - x1)
(-3,0) x1 = -3 and y1 = 0
(0,6) x2 = 0 and y2 = 6
now lets sub
slope(m) = (6 - 0) / (0 -(-3)
m = 6/3
m = 2

now use y - y1 = m(x - x1)
slope(m) = 2
(-3,0) x1 = -3 and y1 = 0
now sub
y - (-3) = 2(x - 0)
y + 3 = 2x - 0
y = 2x - 3
standard form is Ax + By = C
y = 2x - 3
-2x + y = -3 (multiply by -1 to make x positive)
2x - y = 3 <== standard form

Answer 15

y - 2 = 1/2(x + 5) -- distribute through the parenthesis
y - 2 = 1/2x + 5/2 -- now we will add 2 to both sides to get y by itself
y - 2 + 2 = 1/2x + 5/2 + 2 -- combine like terms
y = 1/2x + 5/2 + 2 -- need common denominator which is 2
y = 1/2x + 5/2 + 4/2
y = 1/2x + 9/2

understand ?

Answer 16

do you need that one in standard form also ?

Answer 17

oh yes! thank you:) i understand that one, but i don't understand a part of the (-3,0) and (0,6) one... 0 is y1 not -3, so shouldn't it be y-0=2(x+3)?

Answer 18

no i don't need it in standard form, but thanks

Answer 19

crap...your right...let me do it again
y - 0 = 2(x + 3)
y - 0 = 2x + 6
y = 2x + 6

Ax + By = C
-2x + y = 6 (multiply by -1 to make x positive)
2x - y = -6

Thanks for catching my mistake :)

Answer 20

heheh thank you! ;D

Answer 21

glad to help :)

Answer 22

yes you helped A LOT! I understand everything:D K-bye!