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Mathematics 12 Online
OpenStudy (anonymous):

Write the standard equation of the circle below.

OpenStudy (anonymous):

OpenStudy (anonymous):

just use the standard circle equation (x−h)^2+(y−k)^2=r^2 where (h, k) is the center of the circle r is the radius

OpenStudy (anonymous):

Would the answer be (x-1)^2+(y+2)^2=1?

Directrix (directrix):

@SunshineGirl >>>>(x-1)^2+(y+2)^2=1? NO If the center has coordinates (-1, 2), then the standard form of the circle is found as follows: (x - (-1))^2 + (y - (2))^2 = 1^2 This part of your answer is not correct: (x-1)^2

OpenStudy (anonymous):

switch ur x and y

Directrix (directrix):

@11calcBC >>> switch ur x and y Why?

OpenStudy (anonymous):

Thank you so much,

OpenStudy (anonymous):

i mean the sign my bad

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