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Write the standard equation of the circle below.
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just use the standard circle equation (x−h)^2+(y−k)^2=r^2 where (h, k) is the center of the circle r is the radius
Would the answer be (x-1)^2+(y+2)^2=1?
@SunshineGirl >>>>(x-1)^2+(y+2)^2=1? NO If the center has coordinates (-1, 2), then the standard form of the circle is found as follows: (x - (-1))^2 + (y - (2))^2 = 1^2 This part of your answer is not correct: (x-1)^2
switch ur x and y
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@11calcBC >>> switch ur x and y Why?
Thank you so much,
i mean the sign my bad
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