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solve the inequality |x+6| > 15
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\(\bf |x+6| > 15 \implies \begin{cases} +(x+6) > 15\\ \quad \\ \bf -(x+6) > 15 \end{cases}\)
so you'd get 2 values for "x", one for each scenario
2 values one is negative the other is positive
9 and -21
so it will be one postivie answer and the other one negative?
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yea yea yea
thank you
because it's the absolute value where the numbers inside the | | is positive because it is the distance from zero
x > –21 or x < 9 x < –21 or x > 9 –9 < x < 9 –21 < x < 9 does the sign change?
-21>x>9 is the answer
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