Part 1: Using complete sentences, explain how to find the equation of the line, in standard form and slope–intercept form, passing through (3, 6) and (–2, –4). (4 points) Part 2: Compare the benefits of writing an equation in standard form to the benefits of writing an equation in slope–intercept form. (3 points)
Line equation through two points A(x1,y1) and B(x2,y2) is given by y-y1=(y2-y1)/(x2-x1) (x-x1) in your case y-6=(-4-6)/(-2-3) (x-3) y-6=2(x-3) y=6+2x-6 y=2x
r u there?
yes i am can you please explain with words because i dont understand
It is all to do with linear equation. so, slope–intercept form. is better cause u see slope and intersept point and in standard form all is mixed up
i understand that i dont understand the first part
do you get it?
In order to write an equation of a line, you need a point (intercept) and a slope. You already have a good point to use (3,6) in your slope-intercept form -> y - y = m ( x - x ) -> y - 6 = m ( x - 3 ) Now all you need is the slope. To find the slope you need to (y2-y1) / (x2-x1). So that's [ 6 - (-4) ] / [ 3 - (-2) ] = 10 / 5 = 2 m= 2 so you can add it into your equation. y - 6 = (2) ( x - 3 ) To put it into standard form (y=mx + b) you must solve for y. y - 6 = 2x - 6 y= 2x
i just had a epiphany thankyou
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