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Solve the following equation to get a by itself: H=6a+9c^2
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Subtract then divide. Remember you have to do the same thing to both sides of the =. Where are you stuck?
Move 9c^2 to the LHS and then divide both sides by 6
what do i subtract?
You want to get a by itself. So you have to subtract \(9c^2\). But you have to do that to both sides of the equation. \[H = 6a + 9c^2\]\[H - 9c^2 = 6a + 9c^2 - 9c^2\]\[H - 9c^2 = 6a\]
so the answer would be\[6h-9c^2\] over \[2\]
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o.0 How'd you get that as the answer?
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