Question

How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid?

Unbalanced equation: H2SO4 + NaOH → H2O + Na2SO4

Show, or explain, all of your work along with the final answer.

Answer 1

Is this right?

H2SO4 + 2 NaOH → 2 H2O + Na2SO4

M(NaOH) = M(Na) + M(O) + M(H) = 23 + 16 + 1 = 40 g/mol

M(H2O) = 2M(H) + M(O) = (2 x 1) + 16 = 18 g/mol


From the equation :

2 x 40g of NaOH -----> 2 x 18g of H2O

65,5g of NaOH -----> (36 x 65,5) / 80 = 29,5g of H2O

Answer 2

@Solomonium

Answer 3

Looks perfect and you got your significant figures right too.
Well done!

Answer 4

thx :D

Answer 5

Where does the 36 come from however? in the line:
"65,5g of NaOH -----> (36 x 65,5) / 80 = 29,5g of H2O "

That is my only question :)

Answer 6

Ohhh I see, you multiply with 2 on the molar mass of water and sodium hydroxide. Well nothing wrong with that, but could be left out.

Answer 7

dont steal ppl's work tyler....