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Calculus1
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f(x)=logbase5(X^2+1)^1/2+tan^-1(e^x) ;Dx f(x)
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\[\huge \log_5 (x^2+1)^{\left(\frac{1}{2}+\tan^{-e^x}\right)}\]
@Euler271
lol are you sure this is it?
Oh did I miss the "-1" sign? I guess that would make it tan inverse?
i think so. and it might be a sum of two terms. so [log(stuff)^1/2] + tan^(-1)(e^x)
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Oh true..
\[\large \log_5 (x^2+1)^{\frac12}+\tan^{-1}(e^x)\]
can't be solved with algebra
Alien math! Haha just kiddin.
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