Please help me factor the following equation x^3+x^2-2=0
\[x^3+x^2-2=0\]
One way to solve cubic and higher order equations is to try out a few small values of x such as: 1, -1, 2, -2, etc. If I try x = 1 in x^3+x^2-2 it become 0 that means (x - 1) is a factor. Do synthetic division and figure out the quotient. It will be a quadratic expression which may be able to factor further.
ok i understand how (x-1) is a factor. but what do you mean by 'do synthetic division and figure out the quotient'?
(x - 1) is a factor means: The original expression x^3+x^2-2 = (x - 1){ some lower order expression } We have to figure out what the lower order expression is. So divide (x^3+x^2-2) by (x - 1) to figure out the lower order expression. This division you can do either the long division or if you are familiar with synthetic division you can use that method.
ok thanks
you are welcome.
Join our real-time social learning platform and learn together with your friends!