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Calc help please: sin(xy)=(x^2)cosy, find y prime
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how far are you?
I've always had trouble deriving trigonometric functions.. I don't know where to start
ok, I can get the right side actually. hold on
-(x^2)siny + 2xcosy
but what do I do with the sin(xy)?
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yours = sin(xy ) - x^2cos(y) =0 now take derivative, term by term, first term sin(xy) = cos (xy) * (xy)' = cos (xy) [ y + xy']
got me?
no still trying to understand
yeah it just clicked before you posted that but thank you
the second term?? do it!!
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hey, not finish yet, do the second term, please. You have a long process to get the final answer.
I know I'm working it on paper
cos(xy)(y+xy1) + (X^2)siny - 2xcosy
nup
no?
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