1. Solve 3x − 9 + x > 27 a. x > 4.5 b. x < 4.5 c. x > 9 d. x < 9 3. Maria earns $8 an hour babysitting. Last week Maria made $64. She needs to have at least $150 for vacation. Which inequality can be used to determine how many more hours Maria needs to babysit before she is ready for vacation? a.64x + 8 ≥ 150 b. 8x + 64 ≥ 150 c. 64x + 8 ≤ 150 d. 8x + 64 ≤ 150 5. Solve 4(5m + 6) − 8 ≤ 336. a. m ≤ 16.9 b. m ≤ 16 c. m ≥ 16.9 d. m ≥ 16 6. Solve −4x + 15 > 59. a. x < 11 b. x > −11 c. x < 11 d. x < -11
I lined up number 5 wronggggg,
\[3x − 9 + x > 27 \] combine like terms \[4x-9>27\] add \(9\) \[4x>36\] divide by \(4\) \[x>9\]
On that one, don't you change the sign because you divide?
Like, it wouldn't be x >9 it would be x < 9 because you divided, yeah?
\[4(5m + 6) − 8 ≤ 336.\] add 8\[4(5m+6)\leq 344\] divide by \(4\)\[5m+6\leq86\]
@satellite73
no
only change the inequality if you multiply or divide by a NEGATIVE number 4 is positive
Right, right! Thanks! Could you help me on the rest?
this one \[−4x + 15 > 59. \] you would change the sign
\[-4x+15>59\] subtract 15\[-4x>44\] divide by \(-4\) and now you have to change it becuase \(-4\) is negative \[x<-11\]
you can solve this \[5m+6\leq 86\] right?
I didn't understand number 5? /:
i wrote the solution above, did you see it? or would you like me to repeat it?
lol, don't be rude, I would divide 86 to 4? I don't understand
\[ 4(5m + 6) − 8 ≤ 336.\] add 8\[4(5m+6)\leq 344\]divide by \(4\) \[5m+6\leq 86\] subtract \(6\)\[5m\leq 80\] divide by 5\[x\leq 16\]
OHHHHH! Damn, I see!
kk that is all right?
3?
did 3 first
ooh i see, did 1 first 3 is not done yet
at least means "greater than or equal to" as in "you have to be at least 21 to drink in this bar"
she already has 64 dollars, and makes $8 per hour, go with \[8x+64\geq 150\]
Awesome! :)
awesome is not math on saturday night
Omg, I know :(
How would you put this iquality? If you add 13 to four times a certain number, the sum is less than 265. Let x represent the number. Write an inequality that can be solved to find the value of x.
@satellite73
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