Question

A spherical party balloon is being inflated with helium pumped in at a rate of 5 cubic feet per minute. How fast is the radius growing at the instant when the radius has reached 1 ft?

Answer 1

Do you have multiple guesses on your homework? because I think I have it but Im not 110

Answer 2

yeah it lets me submit it multiple times

Answer 3

alright so what we know is the area of a sphere is pi*r-squared, the derivate of that is 2r and that is 5, so I think r would be 5/2 but im not positive.

Answer 4

would that be the rate at which the radius is growing?

Answer 5

yeah

Answer 6

it wasn't right :(

Answer 7

rate of grpwth = rate of change, aka derivative..

Answer 8

Does it have something do to with the volume of the sphere too? because the questions gives the formula as a hint

Answer 9

question*

Answer 10

try 3.92

Answer 11

nope :/

Answer 12

wtf

Answer 13

I know...I hate this stuff haha

Answer 14

k guys i am ready

Answer 15

ok so volume is 4/3pi r^3

Answer 16

ooo bring it @raffle_snaffle , equivalent exchange

Answer 17

yeah then i plugged in 5 for the radius

Answer 18

look above

Answer 19

above?

Answer 20

i posted another question

Answer 21

@raffle_snaffle oh you need my help?

Answer 22

sure

Answer 23

I'll be back on in a little I'm grabbing food but @kobesaurus let me know if you find the answer!

Answer 24

wait its .397

Answer 25

c

Answer 26

calculator messup

Answer 27

AHHHHH you're awesome! thanks man how did you find it out?

Answer 28

I'll snap a photo and upload it in a sec

Answer 29

alright thank you so much!

Answer 30

np, enjoy that grub

Answer 31

haha I will!