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Mathematics 15 Online
OpenStudy (anonymous):

A survey revealed that 35% of people are entertained by reading books, 28% by watching TV, and 10% are entertained by both books and TV. What is the probability that a person will be entertained through neither a book nor TV?

OpenStudy (anonymous):

neither A is the complementary of A (1-A) or is Union try to write that symbolically

OpenStudy (anonymous):

1-P(A U B)’

OpenStudy (anonymous):

A= 35% B=28% P(A ∩ B)= 10% P(A ∪ B) = 73%

OpenStudy (anonymous):

P(A ∪ B) how do u find that?

OpenStudy (anonymous):

P is the symbol for probability

OpenStudy (anonymous):

So it reads the probability of the union of A and B I made up A and B, A is Books And B is TV

OpenStudy (anonymous):

P(A ∪ B) = P(A)+P(B)-P(A ∩ B)

OpenStudy (anonymous):

So is that the formula for neither or?

OpenStudy (anonymous):

no this for the union, so then find 1- P(A ∪ B)

OpenStudy (anonymous):

that gives me 63%

OpenStudy (anonymous):

sorry 53%

OpenStudy (anonymous):

1-0.53

OpenStudy (anonymous):

got it thanks

OpenStudy (anonymous):

I got 47% which is the amount of people that would be entertained through neither books nor T.V

OpenStudy (anonymous):

That statement almost sounds like Zero to me

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

Is just the way is worded I got it though thanks

OpenStudy (anonymous):

Of the coffee makers sold in an appliance store, 5% have either a faulty switch or a defective cord, 1.9% have a faulty switch, and 1% have both defects. What is the probability that a coffee maker will have a defective cord

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