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Choose the equation that represents the graph below.
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y = -negative three fourthsx + 4 y = -negative four thirdsx + 4 y = three fourthsx - 4 y = 4 thirdsx
i think (y-4)+(x-3)=0
can you find the slope given 2 points ?
That works, or you can start with \(y = mx + b\) and look at the graph.
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y2-y1/x2-x1?
yes, so the 2 points you take are 3,0 and 0,4 find the slope now
m= 4/-3
yup! m= -4/3 which option says that ?
note, in y=mx+c, m= slope
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So it's the second?
yup :)
From the graph, you can see where the line intercepts y, which is (0,4) you know now your b value of y = mx + b from there take two points and find the slope (0,4) and (3,0) 0-4 / 3 - 0 m = -4/3 then plug those values into y =mx + b
Thanks!
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