Question

1. A ten kilogram rock is in geosynchronous orbit about the earth at the orbital radius of 42 thousand kilometers.
calculate the centripetal force

Answer 1

@agent0smith please help me.. I am comparing the answers with my friend and she got different answers than me.. i dont know why

Answer 2

I did this,

T = 24hrs

W= 2 (pi) / T

Fc = mrw^2

for w= 2 (pi) / (86400) = (7.27 x 10^-5

then f = (10 kg) (42000000) (7.27 x 10^-5)
f = 2.22 N

Answer 3

@Loser66

Answer 4

How do you know T = 24?

Answer 5

to me, I just apply F = G m1m2/ r^2

Answer 6

geosynchronous orbit

doesnt that equals 24 hrs which then i convert to seconds?

Answer 7

to my book, it says "A gyosynchoronous satellite is one that stays above the same point on the Earth"

Answer 8

its not a satellite its an orbit meaning time, i googled and told me it gyosynchoronous orbit is 24hrs

Answer 9

yea, you are right about it but I don't see the link between it with the force. My prof indicated about it when we have to find out the distance between 2 objects to find r with
\(r^3= \dfrac{GM T^2}{4\pi^2}\) not to find out the force.
I think you overthought it, just F = Gm1m2/r^2 is ok, don't forget r = radius of the earth + orbital raidius

Answer 10

okay thanks

Answer 11

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