Question

is this slope correct m= y2 – y1 = 0 -330 = -330 = -3 x2 – x1 110 –0 110

Answer 1

what are the 2 points?

Answer 2

0,-330 110,0

Answer 3

\(\bf slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{0-(-300)}{110-0}\implies \cfrac{300}{110}\implies \cfrac{30}{11}\)

Answer 4

the equation is m= y2 – y1 = 0 -330 = -330 = -3
x2 – x1 110 –0 110
What is the slope I think it is -3 but not sure.

Answer 5

it is -330

Answer 6

shoot, I see... then

Answer 7

\(\bf slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{0-(-330)}{110-0}\implies \cfrac{330}{110}\implies 3
\)

Answer 8

thank you. if x=3 than y =1

Answer 9

are you after the equation of the line?

Answer 10

I need to write from the point slope an equation for a linear inequality

Answer 11

\(\bf slope=m=3\qquad x =3\qquad y =1\\ \quad \\
y-y_1=m(x-x_1)\implies y-(1)=3(x-(3))\implies y-1=3x-9\\ \quad \\
y = 3x-8
\)

Answer 12

so 3x/-8

Answer 13

no just 3x -8

Answer 14

how do i substitute x and y in this y=330=? using 3x and -8

Answer 15

not sure what you mean?

Answer 16

If I need to substitute m for the slope and 330,0 for x and y how do i do it

Answer 17

are you still helping me?

Answer 18

.... yes..... I'm just unsure on what you're asking :(

Answer 19

y-330=m(x-0) how would I write the slope (m) using 3x-8 I am not a math pro.

Answer 20

if we disregard the part of x = 3 and y = 1
and instead use the original 2 points for the slope, that is (0,-330) and (110,0)

then using the point-slope form it'll be
\(\bf slope=m=3\qquad x =0\qquad y =-330\qquad \textit{using (0,-330)}\\ \quad \\
y-y_1=m(x-x_1)\implies y-(-330)=3(x-(0))\implies y+330=3x\\ \quad \\
y = 3x-330\)

Answer 21

now if I need to write this in an linear inequality using the point slope how do i do it? what steps do I use to come up with linear inequality?

Answer 22

I need to write an equation for the linear inequality using the point slope. Does this make sense?

Answer 23

yes

Answer 24

let us draw the line y = 3x-330 first

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIzeC0zMzAiLCJjb2xvciI6IiMyQzMyRTgifSx7InR5cGUiOjEwMDAsIndpbmRvdyI6WyIxMDIuNjYiLCIxMTUuNjYiLCItNS45MDAwMDAwMDAwMDAwMDEiLCIyLjEiXX1d

Answer 25

now, notice the line, and let us pick a POINT NOT IN THE LINE
let's say the point (100, 0) is not in the line, so let us use that
\(\bf point\qquad (100,0)\\ \quad \\
y \quad \square \quad 3x-330\implies 0 \quad \square \quad 3(100)-330\implies 0 \quad \square \quad 300-330\\ \quad \\

0 \quad \square \quad -30\)

so which one do you think is bigger? 0 or -30 ?

Answer 26

0

Answer 27

ahh so we can say that, 0 is GREATER than -30, or \(\bf 0 \quad \square \quad -30\implies 0 \quad > \quad -30\qquad thus\\ \quad \\
\textit{we could also say then that}\qquad y > 3x-330\)

Answer 28

Thank you I am so confused how to do this problem. I think I am on the right track, however I am probably over thinking this whole algebra thing.

Answer 29

np

Answer 30

http://www.regentsprep.org/regents/math/algebra/ae85/grineqa.htm

Answer 31

signing off