A tunnel is in the shape of a parabola. The maximum height is 31 m and it is 13 m wide at the base as shown below. Image Attached Below What is the vertical clearance 2 m from the edge of the tunnel? Answer Choices: 2 m 14.9 m 29 m 16.1 m
do you know what a "vertical clearance" is?
@jdoe0001 no
|dw:1382309930592:dw| Find the equation of a parabola, y(x), using your givens. Here y is height and x is distance from center of the parabola. Then find y(6.5 - 2) for your answer.
I'm sorry, I don't understand.
hmm onlyoneze do you drive a car?
yes
Am I suppose to multiply 31 which is y by 4.5?
well. http://onlinesigns.biz/wp-content/uploads/2011/08/Clearance-Sign.png <--- doe that look familiar?
that's what's meant by "vertical clearance"
What is the vertical clearance 2 m \(\bf \color{red}{from}\) the edge of the tunnel?
If you were to go 2 m from the side of the tunnel and look up (from the ground), how high would the ceiling be at that point? That's the clearance. You know the equation of a parabola is \(x^2 = -4py\implies y(x)=\cfrac{-x^2}{4p}\ \ \), where p is the directix. To find p, you can use \(y(6.5)=-31=\cfrac{-(6.5)^2}{4p}\). Once you've got p, to find clearance, you can use \(y(6.5-2)=-31=\cfrac{-(4.5)^2}{4p}\). http://en.wikipedia.org/wiki/Parabola
http://www.oregon.gov/ODOT/CS/ssb/images/tunnels/toothrock.jpg better example, a tunnel shaped like a parabola
@ybarrap is p .34?
so would the vertical clearance be 5.5? @jdoe0001
Wait, wouldn't it just be 29m?
31-2?
Check your calculations, the rest is easy.
You are on the right track, question I have do you understand what we did?
I understand that the vertical clearance is that distance from the highest point, correct?
what you're being asked is to be honest I didn't quite get the wording heheh, I thought it was 29 =) anyhow, what you're being asked is |dw:1382312183085:dw|
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