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Mathematics 13 Online
OpenStudy (anonymous):

7x-10>3x+2

OpenStudy (shamil98):

Try doing the problem, from the previous answers to your questions! You want to get x by itself 7x - 10 > 3x + 2 What do you think the first step would be?

OpenStudy (anonymous):

i always get confuse. Because i dont know which side to move it

OpenStudy (shamil98):

You can x to either side.

OpenStudy (shamil98):

move*

OpenStudy (anonymous):

this is what i did

OpenStudy (anonymous):

7x-10>3x+2 +7x +7x -10>10x+2 -2 -2

OpenStudy (anonymous):

something is wrong in this

OpenStudy (shamil98):

You added a 7x you are supposed to subtract it

OpenStudy (anonymous):

why subtracting

OpenStudy (shamil98):

to get to the other side you want it to be equal to zero +7x - 7x = 0

OpenStudy (anonymous):

i think i get it

OpenStudy (anonymous):

this is a different question but its fractions now

OpenStudy (anonymous):

\[\frac{ 4x-3 }{ 7 }<\frac{ 3 }{ 8}-x\]

OpenStudy (shamil98):

you want to multiply both sides by the denominators to get rid of the fraction 7(4x-3/7) < 7(3/8 - x ) 4x -3 < 21/8 - 7x

OpenStudy (anonymous):

i dont understand how you got 4x-3<21/8-7x

OpenStudy (shamil98):

\[7 \times \frac{ 4x -3 }{ 7 } < 7 (\frac{ 3 }{ 8} - x)\]

OpenStudy (shamil98):

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