7x-10>3x+2
Try doing the problem, from the previous answers to your questions! You want to get x by itself 7x - 10 > 3x + 2 What do you think the first step would be?
i always get confuse. Because i dont know which side to move it
You can x to either side.
move*
this is what i did
7x-10>3x+2 +7x +7x -10>10x+2 -2 -2
something is wrong in this
You added a 7x you are supposed to subtract it
why subtracting
to get to the other side you want it to be equal to zero +7x - 7x = 0
i think i get it
this is a different question but its fractions now
\[\frac{ 4x-3 }{ 7 }<\frac{ 3 }{ 8}-x\]
you want to multiply both sides by the denominators to get rid of the fraction 7(4x-3/7) < 7(3/8 - x ) 4x -3 < 21/8 - 7x
i dont understand how you got 4x-3<21/8-7x
\[7 \times \frac{ 4x -3 }{ 7 } < 7 (\frac{ 3 }{ 8} - x)\]
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