Question

How do you prove this?

Answer 1

<PRQ=<PQA=90 degrees, QR=QA, and <QPC=<RPC. <QCB=<QBC. Prove that RA is parallel to PB.

Answer 2

I think you need to prove that triangles QBC and QAR are similar (to show that <QBC and <QAR are equal) and thus use the opposite exterior angle theorem (using the same two angles) to show that RA and PB are parallel.

Answer 3

Ah, I see now. Thanks!!

Answer 4

You're welcome!