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OpenStudy (anonymous):
4x-3/7<3/8-x I started someone help me finish it
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OpenStudy (anonymous):
\[\frac{ 4x-3 }{ 7 }<7(\frac{ 3 }{ 8 }-x)\]
OpenStudy (anonymous):
i multiplied each side by 7
OpenStudy (anonymous):
and got 4x-3<21/8-7x
OpenStudy (anonymous):
now i dont know what to do after this
OpenStudy (anonymous):
\[4x-3<\frac{ 21 }{ 8 }-7x\]
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OpenStudy (ranga):
Isolate x. Add 7x to both sides.
OpenStudy (anonymous):
why not 4
OpenStudy (ranga):
You can do that too. With 4x you have to subtract it from both sides. With 7x you can dd to both sides.
OpenStudy (anonymous):
i would get the same answer right. Which ever side i used. And it can be with any problem???
OpenStudy (ranga):
Yes.
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OpenStudy (anonymous):
thanks you just cleared everything up for me. I get confuse a lot
OpenStudy (ranga):
you are welcome.
OpenStudy (anonymous):
now do add 3 on both sides
OpenStudy (anonymous):
i have 11x-3<21/8 do i add 3
OpenStudy (ranga):
Yes add 3 to both sides
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OpenStudy (anonymous):
i got 11<5
OpenStudy (anonymous):
wait sorry not that
OpenStudy (anonymous):
\[11x<5\frac{ 5 }{ 8 }\]
OpenStudy (ranga):
make the right side a full fraction than a mixed number.
OpenStudy (anonymous):
how do i do that
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OpenStudy (ranga):
5 + 5/8 = (40 + 5)/8 = 45/8
OpenStudy (anonymous):
i got 45/88
OpenStudy (anonymous):
is this correct
OpenStudy (ranga):
Yes. But it should be x < 45/88
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