Calculate the theoretical yield of ammonia produced by the reaction of 100 g of H2 gas and 200g of N2 gas? 3H2(g) + N2(g)----- 2NH3(g)

Question

Calculate the theoretical yield of ammonia produced by the reaction of 100 g of H2 gas and 200g of N2 gas? 3H2(g) + N2(g)-----> 2NH3(g)

azureilai · Answer

14.279 mol of NH3. I am rounding to the hundredth

anonymous · Answer

@Azureilai can you show me how you got that please

azureilai · Answer

I used something called dimensional analysis.
$$\frac{ 200gN_{2}*1molN_{2}*2molH_{2} }{ 28.014g*1molN_{2}}$$ It basically uses the ratios of each "dimension" to calculate it to the final dimension. 
I first determined in using Nitrogen instead of Hydrogen to calculate this because Nitrogen was the limiting reactant.

anonymous · Answer

thank you @Azureilai

azureilai · Answer

no problem