1/3w + 3 = 2/3w -5
\[\frac{ 1}{ 3 }w +3 \rightarrow or \rightarrow \frac{ 1 }{ 3w }+3 ??\]
The First One.
ok, so first times every number in the equation by 3 \[\frac{ 1 }{3 }w + 3 = \frac{ 2 }{ 3 }w - 5\] \[3(\frac{ 1 }{3 }w + 3) = 3(\frac{ 2 }{ 3 }w - 5)\] \[\frac{ 3 }{3 }w + 9 = \frac{ 6 }{ 3 }w - 15\] \[1w + 9 = 2w - 15\] now balance it out, add 15 to both sides to place the numbers onto the LHS of the equation \[1w + 9 +15 = 2w - 15 +15\] \[1w + 24 = 2w \] then subtract 1w from both sides of the equation to place all of the w's on the RHS of the equation \[1w -1w + 24 = 2w -1w \] \[24 = w \]
Thanks. ^.^
all good, make sense? u understand it all ok?
Yup.! Now I Do. Since You Actually Explained Everything And Didn't Just Show Me The Answer. (:
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