Question

xyz+xy+xz+zy+x+y+z=1000

Answer 1

that's a tough puzzle

Answer 2

factorise

Answer 3

Explain?

Answer 4

xyz+xy+xz+zy+x+y+z=1000
xy(z+1)+z(x+y)+(x+y)+z=1000
...

Answer 5

Where can you go from there?

Answer 6

xyz+xy+xz+zy+x+y+z=1000
(xy)(z+1)+z(x+y)+(x+y)+z
(xy)(z+1)+(x+y)(z+1)+z
(z+1)(xy+x+y)+z
(z+1)(x(y+1)+y)+z

Answer 7

But what are the varibles equal to?

Answer 8

hmm,

Answer 9

Bonus question for a college algebra test that the romanian professor says is 4th grade level for him.

Answer 10

xyz+xy+xz+zy+x+y+z=1000
(xy)(z+1)+z(x+y)+(x+y)+z
(xy)(z+1)+(x+y)(z+1)+z
(z+1)(xy+x+y)+z
(z+1)((x+1)(y+1)-1)+z
(z+1)((x+1)(y+1))-(z+1)+z =1000
(z+1)((x+1)(y+1))-1 =1000
(z+1)((x+1)(y+1))=999
we got it?

Answer 11

Reward me right now!!! i can't wait

Answer 12

Thanks

Answer 13

if you need a unique solution , factories the right hands sides into any three factors,and compare the left and hight hand sides, (there are many possibilities)

Answer 14

*factorise