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How do you convert y=2(x-5)(x+2) into standard form, y=ax^2+bx+c?
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Multiply it.
so would i do 2(x-5) 2(x+2) ?
hi
2(x^2-5x+2x-10)=2x^2-2*3x-10=0 2x^2-6x-10
y=2x^2-6x-10 @ali1029
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y=2(x-5)(x+2) y=(2x-10)(x+2) y=2x(x+2)-10(x+2) \[y=2x^2+4x-10x-20 =2x^2-6x-20\] which is in the form of y=ax^2+bx+c @ali1029
so it would be 2x^2-6x-20 and not 2x^2-6x-10 ?
Yes, it would be 2x^2-6x-20 @ali1029
2x^2−6x−20
thank you so much for explaining and helping! :)
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