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OpenStudy (anonymous):
72 degrees
OpenStudy (anonymous):
because you change pi radians to 180 degrees, so 2(180)/5 = 72
OpenStudy (anonymous):
Thanks! The point (3, -4) is on the terminal side of an angle 0 . What is cos 0 ?
OpenStudy (gorv):
(180/pi ) *(2pi/5)=72 degree
OpenStudy (anonymous):
cos theta = 3/5
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OpenStudy (anonymous):
use (pi) radians = 180 degrees
OpenStudy (anonymous):
becuase you draw the right triangle in quadrant IV, you see that the hypotenuse is 5 from Pythagorean Theorem
OpenStudy (anonymous):
If tan 0 =12/5 and cos 0 < 0, what is sin 0 ?
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
sin theta = 5/13
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OpenStudy (anonymous):
draw the 5-12-13 triangle
OpenStudy (anonymous):
you are a genius
OpenStudy (anonymous):
What is tan 3pi/2 ?
OpenStudy (anonymous):
that is tan (120) = - tan 60 = - sqrt(3)
OpenStudy (anonymous):
Note: error
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OpenStudy (anonymous):
that is tan (270) which is undefined
OpenStudy (anonymous):
3pi/2 = 3(180)/2 = 270
OpenStudy (anonymous):
so tan (270) is undefined.
OpenStudy (anonymous):
What is the reference angle for 120°?
OpenStudy (anonymous):
60?
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OpenStudy (anonymous):
It is 60 degrees.
OpenStudy (anonymous):
Which expression is equivalent to (1 – sin2 x)(sec x)?
OpenStudy (anonymous):
you are currently helping me graduate high school! THANK YOU!
OpenStudy (anonymous):
welcome.
OpenStudy (anonymous):
(1-sin^2x) = cos^2 (x)
so you have cos^2(x)(sec x) = cos x
Reason is that sec x = 1/cos x
and you should know that 1- sin^2(x) = cos^2(x)
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OpenStudy (anonymous):
Final answer is cos x as I showed above.
OpenStudy (anonymous):
Which expression is equivalent to cot t sec t?
OpenStudy (anonymous):
csc t, sin t, tan t, sin^2 t, csc^2 t ?
OpenStudy (anonymous):
cot t = cos t/sin t
and sec t = 1/cos t
so cot t sect t = (cos t/sin t) times 1/cos t = 1/sin t = csc t
OpenStudy (anonymous):
it's csc t?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Which function has a phase shift of pi/2 the right?
OpenStudy (anonymous):
choices?
OpenStudy (anonymous):
one second
OpenStudy (anonymous):
I assume you are looking for cos x
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OpenStudy (anonymous):
because when you shift sin x pi/2 to the right you get cos x
OpenStudy (anonymous):
y = 2sin(1/2x+pi), y = 2sin(2x +pi),
y = 2sin(x +pi/2),y = 2sin(x -pi) , y = 2sin(2x -pi)
OpenStudy (anonymous):
each options is separated by commas
OpenStudy (anonymous):
y = 2sin((x+pi/2)
OpenStudy (anonymous):
x + pi/2 = 0 gives you x = -pi/2
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OpenStudy (anonymous):
What is the domain of y = cot x?
OpenStudy (anonymous):
x cannot be 0,180, 360 or any multiple of 180
OpenStudy (anonymous):
because cot x = cos x/sin x
so a fraction is undefined when the denominator is zero
sin x = 0 when x = 0, 180, 360, etc...
OpenStudy (anonymous):
none of my options are 'undefined'
OpenStudy (anonymous):
(-infinity, infinity), (0, pi), all x= pi/2+pi, all x= pi, all x=pi/2
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OpenStudy (anonymous):
those are my options
OpenStudy (anonymous):
poorly written choices
OpenStudy (anonymous):
You want the domain...the domain is all possible values that x can be
OpenStudy (anonymous):
the best choice would be (0,pi)
OpenStudy (anonymous):
domain exists on (0,pi)
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OpenStudy (anonymous):
yeah this things sucks. .. Simplify the expression: 1/1+cot^2 x
OpenStudy (anonymous):
1 + cot^2(x) = csc^2(x)...
OpenStudy (anonymous):
so 1/csc^2(x) = sin^2(x)
OpenStudy (anonymous):
Final answer is sin^2(x)
OpenStudy (anonymous):
Makes sense?
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OpenStudy (anonymous):
Given tan 0= 4/3 and sin=(-4/5), find cos 0
OpenStudy (anonymous):
yeah. how are you so good at this?
OpenStudy (anonymous):
tan theta = sin theta/cos theta
so, 4/3 = -4/5/cos theta
so cos theta = - 3/5
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
Solve 2cos2x + cosx − 1 = 0 for x over the interval [0, 2.pi. yes!
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OpenStudy (anonymous):
This is a trig equation..I will work it out step-by-step...watch
OpenStudy (anonymous):
k
OpenStudy (anonymous):
are you a math teacher?
OpenStudy (anonymous):
We first factor:
(2cos x - 1)(cos x + 1) = 0
Set each factor equal to 0, we get:
2 cos x - 1= 0, so cos x = 1/2, and x = pi/3 and 5pi/3
cos x + 1 = 0, so cos x = -1, so x = pi
OpenStudy (anonymous):
x = pi/3, pi, and 5pi/3
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OpenStudy (anonymous):
makes sense
OpenStudy (anonymous):
Do you understand?
OpenStudy (anonymous):
yes.. this is the last one to my test.... Which expression is equivalent to tan(-x)cos2x?
OpenStudy (anonymous):
choices?
OpenStudy (anonymous):
-sin xcos x, sin xcos x, tan x + sin2x, tan x − sin2x, -tan x − sin2x
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OpenStudy (anonymous):
tan(-x) = - tan x
cos(2x) = many formulas..
Are you typing your question correctly? I dont see it