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Mathematics 17 Online
OpenStudy (anonymous):

Solve

OpenStudy (anonymous):

\[\frac{ x+1 }{X-5}\le0\]

OpenStudy (anonymous):

@KeithAfasCalcLover

OpenStudy (anonymous):

Can you wa;l me through this

OpenStudy (anonymous):

walk*

OpenStudy (anonymous):

Alright! So are we solving for \(x\)?

OpenStudy (anonymous):

Is the equation: \[\frac{x+1}{x-5}\leq0\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@Luigi0210 I need you D:

OpenStudy (ranga):

Something less than or equal to 0 implies a negative value. a/b can be negative if and b are of opposite signs. That is a < 0 AND b > 0 or a > 0 AND b < 0

OpenStudy (luigi0210):

Let's wait and see what everyone else has to say first.

ganeshie8 (ganeshie8):

@ranga has it i think it looks good to me

OpenStudy (ranga):

The two sets of inequalities to solve are: x + 1 > 0 AND x - 5 < 0 OR x + 1 < 0 AND x - 5 > 0

OpenStudy (anonymous):

ok

OpenStudy (ranga):

x + 1 > 0 AND x - 5 < 0 gives -1 < x < 5 x + 1 < 0 AND x - 5 > 0 gives x < -1 AND x > 5 (not possible) So the solution is -1 < x < 5 Since the inequality had <= sign I will say the solution is -1 <= x < 5

OpenStudy (anonymous):

Ohh OK

OpenStudy (anonymous):

would that be -1 less than or equal to x less than 5?

OpenStudy (ranga):

Yes.

OpenStudy (anonymous):

Thanks!!

OpenStudy (ranga):

You are welcome.

OpenStudy (anonymous):

Nice goat? btw

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