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OpenStudy (anonymous):
\[\frac{ x+1 }{X-5}\le0\]
OpenStudy (anonymous):
@KeithAfasCalcLover
OpenStudy (anonymous):
Can you wa;l me through this
OpenStudy (anonymous):
walk*
OpenStudy (anonymous):
Alright! So are we solving for \(x\)?
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OpenStudy (anonymous):
Is the equation:
\[\frac{x+1}{x-5}\leq0\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
@Luigi0210 I need you D:
OpenStudy (ranga):
Something less than or equal to 0 implies a negative value.
a/b can be negative if and b are of opposite signs.
That is a < 0 AND b > 0 or
a > 0 AND b < 0
OpenStudy (luigi0210):
Let's wait and see what everyone else has to say first.
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ganeshie8 (ganeshie8):
@ranga has it i think it looks good to me
OpenStudy (ranga):
The two sets of inequalities to solve are:
x + 1 > 0 AND x - 5 < 0 OR
x + 1 < 0 AND x - 5 > 0
OpenStudy (anonymous):
ok
OpenStudy (ranga):
x + 1 > 0 AND x - 5 < 0 gives -1 < x < 5
x + 1 < 0 AND x - 5 > 0 gives x < -1 AND x > 5 (not possible)
So the solution is -1 < x < 5
Since the inequality had <= sign I will say the solution is -1 <= x < 5
OpenStudy (anonymous):
Ohh OK
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OpenStudy (anonymous):
would that be -1 less than or equal to x less than 5?