Question

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Answer 1

Discriminant = b^2 - 4ac

In this problem, a = 2, b = 4, c = -2

so, discriminant = 4^2 - 4(2)(-2)
= 16 + 16
= 32

Answer 2

For a quadratic of form: \(ax^2+bx+c\), the discriminant, \(D\), is:
\[D=b^2-4ac\]
So therefore, with a, b, and c values of 2, 4, -2 (respectively) we have:
\[D=4^2-4(2)(-2)=16+4(2)(2)=16+16=32\]