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Mathematics 10 Online
OpenStudy (anonymous):

i have no idea how to check the feasible point and need help with the problems on five i said: If 9 + 27 = 36 Then 9 x 2 = 18 and 81 So: $ 18 + $81 = $99?

OpenStudy (anonymous):

OpenStudy (anonymous):

typo... 5. If 9 + 27 = 36 Then 9 x 2 = 18 and 3 x 27 = 81 So: $ 18 + $81 = $99

OpenStudy (loser66):

I don't understand what you are doing

OpenStudy (anonymous):

itt is for problem 5 on the bottom of the page, im not sure where to begin on the previous questions

OpenStudy (anonymous):

i mean the last page has problem 5

OpenStudy (loser66):

99

OpenStudy (anonymous):

ok :) so how do i start on problem 3?

OpenStudy (loser66):

you know why?

OpenStudy (loser66):

(9,27) from your graph,

OpenStudy (loser66):

9*2 + 27*3

OpenStudy (anonymous):

the amount that candy bar x cost and candy bar y cost times the max sold for each 2 x 9 and 3 x 27

OpenStudy (anonymous):

when it comes to the first how would i graph the last or would i just get a zero?

OpenStudy (loser66):

don't confuse me, which problem are we working on?

OpenStudy (anonymous):

sorry.. it is the first one on the doc problem 3

OpenStudy (loser66):

find out feasible region?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

wait i see what you mean

OpenStudy (anonymous):

it is problem 2

OpenStudy (loser66):

3not 2

OpenStudy (anonymous):

right

OpenStudy (loser66):

(0,0),(9,27),(36,0)

OpenStudy (anonymous):

ah i see, in my lesson it was not clear how they had it shown, ad on problem 2 would i end up with a zero when it comes too x + 2y (<,=) 12

OpenStudy (loser66):

i don't know how to do it. sorry. hehehe

OpenStudy (anonymous):

lol np

OpenStudy (anonymous):

what about problem 4?

OpenStudy (anonymous):

looking at it i seems i need to fill in the points to get my answers

OpenStudy (loser66):

surely it is the last one

OpenStudy (anonymous):

ok so 81 for the max on y candy bars

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