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Mathematics
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The equation of a hyperbola is shown.
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http://www.jfkcougars.org/ourpages/auto/2013/2/5/43231143/Conics-Formula-Sheet.pdf see the section on hyperbolas. For x^2/25 - y^2/4 = 1 a^2 = 25, b^2 = 4 Your asymptotes will be \[\large y = \pm \frac{ b }{ a }x\]
4/25?
a^2 = 25, b^2 = 4 those are a and b squared. You need to find a and b (take the square root)
5/2x and -5/2x
?
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Almost... but it should be the other way around... \[\large y = \pm \frac{ b }{ a }x\] a^2 = 25, so a = 5 b^2 = 4, so b =2
ohhh ok tht makes sense lol
Good :D
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