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Mathematics 13 Online
OpenStudy (anonymous):

The equation of a hyperbola is shown.

OpenStudy (agent0smith):

http://www.jfkcougars.org/ourpages/auto/2013/2/5/43231143/Conics-Formula-Sheet.pdf see the section on hyperbolas. For x^2/25 - y^2/4 = 1 a^2 = 25, b^2 = 4 Your asymptotes will be \[\large y = \pm \frac{ b }{ a }x\]

OpenStudy (anonymous):

4/25?

OpenStudy (agent0smith):

a^2 = 25, b^2 = 4 those are a and b squared. You need to find a and b (take the square root)

OpenStudy (anonymous):

5/2x and -5/2x

OpenStudy (anonymous):

?

OpenStudy (agent0smith):

Almost... but it should be the other way around... \[\large y = \pm \frac{ b }{ a }x\] a^2 = 25, so a = 5 b^2 = 4, so b =2

OpenStudy (anonymous):

ohhh ok tht makes sense lol

OpenStudy (agent0smith):

Good :D

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