Ask
your own question, for FREE!
Calculus1
12 Online
Find a Cartesian equation for the curve and identify it. r=8tanxsecx
Still Need Help?
Join the QuestionCove community and study together with friends!
tanxsecx? Are you sure it isn't \[\Large r = 8\tan(\theta) \sec(\theta)\]?
yeah its r = 8 tan θ sec θ :d
Okay, these are all you really need for that: \[\Large r= \sqrt{x^2+y^2}\]\[\Large \tan(\theta) = \frac{y}x\] \[\Large x = r\cos(\theta)\]
scratch that, for this particular question, you don't actually need the first one \[\large r = \sqrt{x^2+y^2}\]
(rcosθ)^2=8(rsinθ) is that right:d
Still Need Help?
Join the QuestionCove community and study together with friends!
Actually, yes. But that equation is still not Cartesian, though I have a feeling you already know how to fix that ;)
And also (as you well know, I guess) \[\Large y = r\sin(\theta)\]
thanks.d
x^2 = 8y right :d
Yup. That's a parabola XD
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
abby2blessed:
How do you guys feel about second chances? Concerning relationships, both romantic and otherwise.
TJH:
love Love, it comes, it goes But what if it stayed stayed in the silence the storm stayed when the world was loud for me it's different; it left when it was
Puffer:
General question what came first the chicken or the egg itu2019s a trick question
Bounty:
the world keeps moving fast and I'm stuck in a time lapse all I need is a minute
Bounty:
can I get so tips on how to start my journey into semi-realism art also on how to
Strawberryluna:
Read my poem. Im not for criticism its a poem I wrote after my breakup: Youu2019ll never understand the way you made me break, I hate that I still love you
Bounty:
first poem in a min- (tittle)? one moment i'm fine I smile till my face burns I laugh till I cant breath Then I cry I wonder where I went wrong I listen to
Twaylor:
3d printing a glider (for 150 pound 5'8 person - prolly should make it for up to
3 days ago
0 Replies
0 Medals
4 days ago
4 Replies
3 Medals
4 days ago
5 Replies
1 Medal
1 week ago
4 Replies
0 Medals
2 weeks ago
0 Replies
0 Medals
5 days ago
5 Replies
2 Medals
3 weeks ago
5 Replies
1 Medal
3 weeks ago
5 Replies
0 Medals