What are the solutions of 3x2 = 18x?

x = 0, x = 6

x = 0, x = −6

x = 3, x = 6

x = 3, x = −6

Question

What are the solutions of 3x2 = 18x?

 x = 0, x = 6

 x = 0, x = −6

 x = 3, x = 6

 x = 3, x = −6

anonymous · Answer

@jigglypuff314

anonymous · Answer

Can you teach me?

jigglypuff314 · Answer

you can divide both sides by 3 so you get
x^2 = 6x
and x^2 = x*x
so then you can divide both sides by x

anonymous · Answer

by x you mean 18 or just x?

jigglypuff314 · Answer

you would have divide both sides by 3 first so x^2 = 6x

anonymous · Answer

Will it be D?

jigglypuff314 · Answer

no... whoops, sorry I had explained it wrong
ignore what I said before... umm
you would subtract 18x from both sides so
3x^2 - 18x = 0         then factor out a 3x using the distributive property so
3x(x - 6) = 0

anonymous · Answer

Ohhh so it would be B?

jigglypuff314 · Answer

to find x from 3x(x - 6) = 0   you would set each part equal to 0 so
3x = 0              and               x - 6 = 0

anonymous · Answer

I'm confused.

jigglypuff314 · Answer

to made number times number = 0 true, either of the numbers has to equal 0
so to find x from 3x(x - 6) = 0    x times minus or whatever number has to equal 0 so
find the values of x when
3x = 0              and               x - 6 = 0

anonymous · Answer

So it's D?

jigglypuff314 · Answer

3x = 0              and               x - 6 = 0
  x = 0                                     + 6   +6
                                                   x = 6

it would be A because x = 0 and x = 6

tkhunny · Answer

$3x^{2} = 18x$

$x^{2} = 6x$

$x^{2} - 6x = 0$

$x\cdot(x-6) = 0$

$x = 0\;or\;x-6 = 0$

$x = 0\;or\;x = 6$