Please help. Solve the equation

(4x+1)(x-3)=9

Question

Please help. Solve the equation

(4x+1)(x-3)=9

tkhunny · Answer

Write it in standard form.  This requires "= 0".  9 is no good in that spot.

mertsj · Answer

1.  Multiply the two binomials
2.  Subtract 9 from both sides.
3.  Try to factor
4.  Set each factor equal to 0
5.  Solve each equation.

mertsj · Answer

If it won't factor, plug it into the quadratic formula.

anonymous · Answer

FOIL the equation to get this;
$$4X^2+X-12X-3=9$$
So we get
$$4X^2-11X=6$$
Bring 6 to the left side and set it equal to 0
$$4X^2-11X-6=0$$
Now factor to get
$$(2x-6)(2X+1)=0$$
Set each equal to 0 and solve
$$2X-6=0$$
$$2X=6$$
$$X=3$$
$$2X+1=0$$
$$2X=-1$$
$$X=-(1/2)$$
So $$X= -(1/2),3$$

mertsj · Answer

@AEYES13 -3-9=-12

anonymous · Answer

@Mertsj good catch it would have worked had that actually worked at it would be positive 12 at the top

mertsj · Answer

Yes and will not factor.