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find the limit of the trigonometric function. lim as x approaches 0 sec2x
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just plug in 0 for x, you get sec(0) = 1
I bet its really easy but I don't see why its one
The value of sec (0) is 1. Why? sec (0) = 1/cos(0) = 1/1 = 1 secant function is the reciprocal of the cosine function.
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can that be shown on the unit circle
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yes
can you show me
On the unit circle, a circle whose radius is 1 and center is at (0,0). Look at the point (0,1). The x-coordinate is cos x. So cos 0 = 1. Since cos 0 = 1, then sec 0 = 1 becuase secant and cosecant are reciprocal functions.
I think I kind of see it...so lets say the radius for the unit circle was two instead of 1. the sec of zero would be 2
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here u go
exactly
ok thanks
welcome.
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