Please help me with my Algebra II
Consider the function f (x) = (1/3)x + 2
a. Find the inverse of f(x) and name it g(x). Show and explain your work.
b. Use function composition to show that f(x) and g(x) are inverses of each other.

Question

Please help me with my Algebra II
Consider the function  f (x) = (1/3)x + 2
a.	Find the inverse of f(x) and name it g(x). Show and explain your work.
b.	Use function composition to show that f(x) and g(x) are inverses of each other.

anonymous · Answer

Anyone?

anonymous · Answer

The inverse of a function is found by interchanging x with y, and y with x, AND then solving for y.

Since f(x) = (1/3)x + 2, that means y = (1/3)x + 2

The inverse is x = (1/3)y + 2
Now, solving for y, we have

x - 2 = (1/3)y

Now multiply both sides by 3, we get y = 3(x-2) or 3x - 6

So the inverse is 3x - 6. We say g(x) = 3x - 6

anonymous · Answer

So was that all for A? I am soo confused!

anonymous · Answer

yes. What are you confused about?

anonymous · Answer

I think I got it after looking through that for a while... 
Now, How does function composition work? My teacher wasn't the greatest at describing this lesson.

anonymous · Answer

I managed to figure out the rest! Thanks!