Question

PLEASE HELPP!!!
what is the formula of a line that is perpendicular to y=1/3x+9 and includes the point (3,4)

Answer 1

The slope of your second line is going to be the opposite reciprocal of your first line.
The slope formula is
y=mx+b
in order to find b, plug in your slope and points into the formula
(y-y1)=m(x-x1)

Answer 2

please show work

Answer 3

i dont understand how to do this

Answer 4

Well, do you know what an opposite reciprocal is?

Answer 5

no

Answer 6

@Azureilai ???

Answer 7

@Azureilai hello?????

Answer 8

Ok, so lets consider the fraction 1/2. the opposite reciprocal would be -2/1. The slope of a line is usually in a fraction, so what you do is you flip the numerator and the denominator of the fraction and negate it. (If the fraction was positive, it becomes negative, if it was negative then it becomes positive.) Can you follow so far?

Answer 9

yes

Answer 10

Good, so what do you think will be the opposite reciprocal of 1/3 ?

Answer 11

-3/1

Answer 12

yes you are correct. Now are you familiar with the point slope form?

Answer 13

y=mx+b??

Answer 14

Thst is the slope intercept form. Point slope form is
(y-y1)=m(x-x1)
You can use it to solve for b in the
y=mx+b
(since we have already determined the slope, which is -3, all we need now is the b value.)
What you do in the new formula is plug in you points (3,4,) into the equation and isolate y again to one side. so
(y-4)=-3(x-3)
Solve for y

Answer 15

@Azureilai i dont know how to solve for y

Answer 16

Ok, lets consider the right part of the equation first, can you distribute the -3 in
-3(x-3)?

Answer 17

@Azureilai can u please draw it?

Answer 18

do you get it?