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prove that cos(a+b).cos(a-b) = 1-(sin^a+sin^b)
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^ does this mean to the power ?
it is the square
cos(a+b).cos(a-b)=(cos2a+cos2b)/2 =1/2*[1-2sin^2a+1-2sin^2b] =1/2*2[1-(sin^2a+cos^2b)] =1-(sin^2a+cos^2b)
did you get the previous solution?
* does it mean multiplication ?
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yes
you could work this way too cos(A+B).cos(A-B) =(cosA cos B - sinAsinB)(cosA cos B +sinAsinB) and then multiply the terms
@RED123url : i can't answer the questions :(
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