how would i make a f(x) equation into a porabala

Question

anonymous · Answer

f(x) = x^2

anonymous · Answer

ok the equation i want to make into a porabala on a graph is f(x)=1(x+2)^2+8

thejax · Answer

Quiet Easy!

anonymous · Answer

That is a a parabola. You mean how do you graph it?

thejax · Answer

The standard form of a parabola's equation is generally expressed: $$y=ax^2+bx+c$$ The vertex form of a parabola's equation is generally expressed as : $$y=a(x−h)^2+k$$ (h,k) is the vertex If a is positive then the parabola opens upwards like a regular "U". (same as standard form) If a is negative, then the graph opens downwards like an upside down "U".(same as standard form) If |a| > 1, the graph of the parabola widens. This just means that the "U" shape of parabola stretches out sideways . If |a| < 1, the graph of the graph becomes narrower(The effect is the opposite of |a| > 1).

anonymous · Answer

ok so when im graphing it the vertex would be 8 and the x points would be 2?

thejax · Answer

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