Question

Help me solve this?

Answer 1

I already know that the restriction is 3.

Answer 2

(x - 2(x - 3) is the numerator factor

Answer 3

\[\frac{ x^2 - 5x + 6 }{ x^2 - 9 } = \frac{ (x-2)(x-3) }{ (x+3)(x-3) } = \frac{ x-2 }{ x+3 }\]

notice that +3 is not the only restrition

Answer 4

restriction*

Answer 5

so +- 3 then?

Answer 6

yes

Answer 7

So that's it?

Answer 8

yes

Answer 9

Okay, thanks!