Question

What is the concentration of a solution prepared by adding 8.0 mL of 0.10 M HCl to 100.00 mL of water.

Answer 1

Use \[M _{1}V _{1}=M _{2}V _{2}\].Your are trying to find M1 (The concentration of the solution). Your V1 8.0 mL, your M2 is 0.10 M, and your V2 is 100.00 mL.

Answer 2

Its an algebra problem, just plug and chug. The units will cancel for mL leaving you with M (Molarity/ Concentration as your final answer.

Answer 3

Oh, I though V2 would give me the concentration of water.

Answer 4

No, V is for volume, and M is for Molarity

Answer 5

:)

Answer 6

thank you

Answer 7

No problem!

Answer 8

medals are appreciated!

Answer 9

How do I give one?
I am new to this

Answer 10

click on button that says best response:)

Answer 11

ahh Got it. Can I ask another question while your still here?

Answer 12

thank you! and yes you may

Answer 13

how would I
Calculate the expected volume of 0.10 M NaOH necessary to be added to the solution above (in question 1) to reach the equivalence point.

Answer 14

question 1 being the .008 M solution using M1V1=M2V2

Answer 15

give me a minute okay

Answer 16

For the first problem, I misread the qusetion, the variables and numbers got mixed, but what value did you get for question 1?

Answer 17

question for problem asked Calculate the concentration of a solution prepared by adding 8.0 mL of 0.10 M HCl to 100.00 mL of water.
So using M1V1=M2V2 I got the molarity to be 0.008M
which I still feel a little uneasy about. But assuming that 0.008M is correct how would I find the amount of Base needed to reach equivalence point?

Answer 18

I just calculated it because I felt unsure off what I gave you, but 0.008M is definitely the correct answer!

Answer 19

now let me work out the second part, give me a minute

Answer 20

No problem . Thank you very much for your help.

Answer 21

Once again this is the question for part B:
Calculate the expected volume of 0.10 M NaOH necessary to be added to the solution above (in question 1) to reach the equivalence point.

Answer 22

No problem! So we are using the dilution formula again which is the \[M _{1}V _{1}=M _{2}V _{2}\]. For part B, we use the molarity and volume from part A, and use these as our M1 and our V1. So, M1=0.008M, V1=100.00mL. The M2=0.10M (which was given) and we are finding V2.

Answer 23

let me know what you get, i'll calculate along with you so you can check your answer

Answer 24

I got 8mL

Answer 25

perfect!

Answer 26

Do you have to convert to Liters, or can we keep it in mL?

Answer 27

I just realized I made a mistake M1 is not 0.008M

Answer 28

thats the right answer based on the information you gave me, I just mixed up the variables and values when I gave you the numbers to plug in, but I corrected it.

Answer 29

I forgot to convert ml to L I just multiplied ml with L. So the solution would be 8*10^-6

Answer 30

for M but I just realized my mistake, thank you very much. I think I got the hang of it.

Answer 31

(: