Question

Find a quadratic function that has zeroes -4 and 9 and a graph that passes through (3,5).

Answer 1

y = (x + 0) (x+4) (x-9) <-do you see how I set this up given the info you had?
y = x^3 - 5x^2 - 36x <- just simplifying it out

now, adapt the equation to meet the point (3,5)
y = (3)^3 - 5 (3)^2 - 36 (3)
y = -126
so we need y to be 5, not -126, so we will add 131
y = x^3 - 5x^2 - 36x +131
y = (3)^3 - 5 (3)^2 - 36 (3) +131
y = 5

make sense?

Answer 2

How did you get x+0? 0 isn't a root and it says /quadratic equation/

Answer 3

I'm probably misunderstanding the question then, i though it said zeros

Answer 4

zeroes meaning roots. But I've finished the problem now.

Answer 5

ok! ^_^