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@vtm386 Lessons.....
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ok im here
OK lets start from factoring
ok could you factor the problem \[3x^2 + 4x = 2\]
I think no!
For sure not, because 2 would be 2 times 1 and 2 &1 never add up to 4. See?
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ok so how would you do that problem?
would you use the completing the square?
At first,, in any case, I would subtract 2 from both sides.
\[3x^2+4x=2\] \[3x^2+4x-2=2-2\] \[3x^2+4x-2=0\] this is the form, to even start choosing the method. Set it equal to zero. Right, @vtm386?
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Yup!
Now, lets see, have you ever factored anything before?
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