d/dx (f(2x^2)) = 7x^4 Find f'(x)
\[\frac{ d }{ dx } f(2x^2))=7x^4\]
Hmmmmmmmmmmmmm...
This is alongs the lines that I'm thinking...\[\Large f'(2x^2)\quad=\quad 7x^4\quad=\quad C(2x^2)^2\]
Wait thats the wrong problem.......
oh lol
Ill post new 1 its just a few numbers changed
\[d/dx (f(2x^4))=7x^3\]
first step i got was \[f'(2x^4)=7x^3\]
f' (2x^4)*8x^3 = 7x^3
\[f'(2x^4)=\frac{ 7 }{ 8 }\]
Im there.... i need to find f'(x)
So you chain ruled on the left? Hmm looks like you're on the right track!
So you determined that the derivative function is `constant`. So regardless of what value you plug into the function, 2x^4, x, a bajillion, it will always come back as 7/8. \[\Large f'(2x^4)\quad=\quad\frac{7}{8}\]\[\Large f'(200x^9)\quad=\quad\frac{7}{8}\]\[\Large f'(x)\quad=\quad?\]
still 7/8
yessss.. i think that's what we're looking for at least +_+
O.O that was so easy
can you help me with this word problem?
i can try :u
A spherical balloon is inflated so that its volume is increasing at the rate of 2.7 ft^3/min. How rapidly is the diameter of the balloon increasing when the diameter is 1.8 feet?
The diameter is increasing at____ft/min
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