Pre-calculus help.
@ganeshie8
@ranga
From the graph f(x) we can find f(x) for a few values of x: x f(x) 0 3 1 2 2 1 3 0 4 1 Problem 52) y = f(x - 1) + 3 Find y for a few values of x x y 1 f(1-1) + 3 = f(0) + 3 = 3 + 3 = 6 (f(0) gotten from the previous table) 2 f(2-1) + 3 = f(1) + 3 = 2 + 3 = 5 3 f(3-1) + 3 = f(2) + 3 = 1 + 3 = 4 4 f(4-1) + 3 = f(3) + 3 = 0 + 3 = 3 5 f(5-1) + 3 = f(4) + 3 = 1 + 3 = 4 So which graph does y look like?
There is another way to do this problem. Find the equation of f(x) from the graph. Then see what kind of horizontal and vertical translation of f(x) will lead to y = f(x - 1) + 3 and you can figure out which graph represents y = f(x - 1) + 3.
I don't understand :/
Wait would it be g?
If you don't follow the previous reply see the table in the reply before that. Which graph has the points I created in the table: (1, 6), (2, 5), (3, 4), (4, 3), (5,4)?
Yes! g
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