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Find a Cartesian equation for the curve given by the polar equation: r+6cos(theta)=0
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\[r ^{2}+6r \cos \theta = 0\]
\[x ^{2}+y ^{2}+6x=0\]
it says the answer is (x+3)^2 + Y^2 = 9 can you take me through the process?
After my previous work is done, this should be obvious
DO you know a process called " Completing the Square " Your teacher should have taught you that
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plus 9 on BOTH sides. x^2+y^2+6x+9=9
notice that x^2+6x+9 is just x+3)^2, so (x+3)^2+y^2=9 but your teacher should accept my answer
@mlimsiaco12
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