for A and B this X^3-AX^2+X-B divide on X^2+X-6
i need to find A and B..

Question

for A and B this X^3-AX^2+X-B divide on X^2+X-6
i need to find A and B..

anonymous · Answer

This is a bit challenging!
If  X^3-AX^2+X-B is going to divide  X^2+X-6, then
X^3-AX^2+X-B = (X^2+X-6)(X + ?) for some ? that we need to figure out.

anonymous · Answer

frustrating question (:

anonymous · Answer

the answers is -8 and 42

anonymous · Answer

I messed up on one thing. Now it's fixed
Multiplying everything out and simplifying, you get
X^3-AX^2+X-B = x^3 + (1 + ?) x^2 + (? - 6)x - 6?
And from the symmetry here, we know ? - 6 = 1 and thus ? = 7

anonymous · Answer

-A = 1 + ? implies A = -8
B = 6? implies B = 42

anonymous · Answer

Normally I walk through things interactively, but this one seemed so tough, I thought I'd just put the whole thing out here. Any questions? There may be other approaches, but that's the best way I can think of. Perhaps you could do it a long division way or something.

anonymous · Answer

umm.. no questions. thanks man!

anonymous · Answer

hehe...sure, no problem.