Question

What are the solutions of the equation: z^2 - 12z + 36 = 0?

Answer 1

http://www.1728.org/quadratc.htm

Answer 2

put the values of indices in the calcuator

Answer 3

Do NOT use the quadratic formula on this on. Much, much easier to factor this one. Always see if you can factor first.

Answer 4

z^2 - 12z + 36 = 0
(z )(z ) = 0
Do you know how to figure out what goes in the ( ) ( ) 's ?

Answer 5

nope

Answer 6

u want to verify the answer or learn to solve it?

Answer 7

z^2 - 12z + 36 = (z - 6)(z - 6)
So we have
(z - 6)(z - 6) = 0
z - 6 = 0
z = 6
There's only 1 solution on this one.

Answer 8

z^2 - 12z + 36 = 0? Just factor it pretending the Z is an X so you get (X-6)(X-6) so x=6 or z=6 and since Z is only squared there will only be 2 solutions. ^^^^^ The answer before is right except there will be 2 solutions.

Answer 9

i just want the and the explaintion lol... have no more patients anymore

Answer 10

No there is only one solution. x = 6 What is the other solution?

Answer 11

If you cannot understand it from Me and @BangkokGarrett then its hopeless. And yes sorry for this one there is only 1 solution sorry bangkok

Answer 12

Factoring is tricky for a lot of students. Master that skill and you will benefit a great deal in future math courses.

Answer 13

^^^ that's for sure. Factoring is one of the most common tools you will use throughout your math career.

Answer 14

thank for your help i got it