Why does 1/k(k+1) = 1/k - 1/k+1 this is in calc 2, it says it used partial fractions. I'm doin series mathematics

Question

goformit100 · Answer

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hartnn · Answer

$\huge \dfrac{1}{k(k+1)}= \dfrac{A}{k}+\dfrac{B}{k+1}$

so, from that 
$\Large 1 = A(k+1)+Bk$

to find A, put  k=0
to find B put k=-1

what u get ?

anonymous · Answer

I see what I did wrong, thanks. Got the right answer

hartnn · Answer

cool! 
and a welcome from me too :)
$\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} $