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-(1/4) sin (x/2) = 0 , [0,4pi] How do I find the value of x? Thank youu
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so, sin (x/2) =0 for which angles is sin =0 in the range 2 to 2 pi ??
sorry, range, 0 to 2 pi***
um.... I don't really know for the range... but the interval is the domain so @hartnn
oh yes, ok. so for which angles is sin ratio =0 for domain of x from 0 to 2pi ?
0 and pi
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and 2pi too, right ? so you know that sin 0 = 0, sin pi =0 and sin 2pi =0 ? that means, x/2 = 0 or x/2 = pi or x/2 = 2pi from these , what are the values of x we get ?
oohhh I got 0, 2pi and 4pi is that right?
absolutely! :)
Thank you! :)
welcome ^_^
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